Elliptic Functions
carlson_rc (x, y) — Function
Carlson’s RC integral is defined by
$$R_C(x, y) = \frac{1}{2} \int_0^{\infty} \frac{1}{\sqrt{t+x}(t+y)}, dt$$
$$R_C(x, y) = \frac{1}{2} \int_0^{\infty} \frac{1}{\sqrt{t+x}(t+y)}, dt $$
See https://arxiv.org/pdf/math/9409227Numerical Computation of Real or Complex Elliptic Integrals for more information.
This integral is related to many elementary functions in the following way:
$$\eqalign{ \log x &= (x-1) R_C\left(\left({\frac{1+x}{2}}\right)^2, x\right), \quad x > 0 \cr \sin^{-1} x &= x R_C(1-x^2, 1), \quad |x| \le 1 \cr \cos^{-1} x &= \sqrt{1-x^2} R_C(x^2,1), \quad 0 \le x \le 1 \cr \tan^{-1} x &= x R_C(1,1+x^2) \cr \sinh^{-1} x &= x R_C(1+x^2,1) \cr \cosh^{-1} x &= \sqrt{x^2-1} R_C(x^2,1), \quad x \ge 1 \cr \tanh^{-1}(x) &= x R_C(1,1-x^2), \quad |x| \le 1 }$$
$$\eqalign{ \log x &= (x-1) R_C\left(\left({\frac{1+x}{2}}\right)^2, x\right), \quad x > 0 \cr \sin^{-1} x &= x R_C(1-x^2, 1), \quad |x| \le 1 \cr \cos^{-1} x &= \sqrt{1-x^2} R_C(x^2,1), \quad 0 \le x \le 1 \cr \tan^{-1} x &= x R_C(1,1+x^2) \cr \sinh^{-1} x &= x R_C(1+x^2,1) \cr \cosh^{-1} x &= \sqrt{x^2-1} R_C(x^2,1), \quad x \ge 1 \cr \tanh^{-1}(x) &= x R_C(1,1-x^2), \quad |x| \le 1 } $$
Also, we have the relationship
$$R_C(x,y) = R_F(x,y,y)$$
$$R_C(x,y) = R_F(x,y,y) $$
Some special values:
$$\eqalign{R_C(0, 1) &= \frac{\pi}{2} \cr R_C(0, 1/4) &= \pi \cr R_C(2,1) &= \log(\sqrt{2} + 1) \cr R_C(i,i+1) &= \frac{\pi}{4} + \frac{i}{2} \log(\sqrt{2}-1) \cr R_C(0,i) &= (1-i)\frac{\pi}{2\sqrt{2}} \cr }$$
$$\eqalign{R_C(0, 1) &= \frac{\pi}{2} \cr R_C(0, 1/4) &= \pi \cr R_C(2,1) &= \log(\sqrt{2} + 1) \cr R_C(i,i+1) &= \frac{\pi}{4} + \frac{i}{2} \log(\sqrt{2}-1) \cr R_C(0,i) &= (1-i)\frac{\pi}{2\sqrt{2}} \cr } $$
carlson_rd (x, y, z) — Function
Carlson’s RD integral is defined by
$$R_D(x,y,z) = \frac{3}{2} \int_0^{\infty} \frac{1}{\sqrt{t+x}\sqrt{t+y}\sqrt{t+z},(t+z)}, dt$$
$$R_D(x,y,z) = \frac{3}{2} \int_0^{\infty} \frac{1}{\sqrt{t+x}\sqrt{t+y}\sqrt{t+z},(t+z)}, dt $$
See https://arxiv.org/pdf/math/9409227Numerical Computation of Real or Complex Elliptic Integrals for more information.
We also have the special values
$$\eqalign{ R_D(x,x,x) &= x^{-\frac{3}{2}} \cr R_D(0,y,y) &= \frac{3}{4} \pi y^{-\frac{3}{2}} \cr R_D(0,2,1) &= 3 \sqrt{\pi} \frac{\Gamma(\frac{3}{4})}{\Gamma(\frac{1}{4})} }$$
$$\eqalign{ R_D(x,x,x) &= x^{-\frac{3}{2}} \cr R_D(0,y,y) &= \frac{3}{4} \pi y^{-\frac{3}{2}} \cr R_D(0,2,1) &= 3 \sqrt{\pi} \frac{\Gamma(\frac{3}{4})}{\Gamma(\frac{1}{4})} } $$
It is also related to the complete elliptic integral of the second
kind, $E$,
(elliptic_ec) as follows
$$E(m) = R_F(0, 1 - m, 1) - \frac{m}{3} R_D(0, 1 - m, 1)$$
$$E(m) = R_F(0, 1 - m, 1) - \frac{m}{3} R_D(0, 1 - m, 1) $$
See also: elliptic_ec.
carlson_rf (x, y, z) — Function
Carlson’s RF integral is defined by
$$R_F(x,y,z) = \frac{1}{2} \int_0^{\infty} \frac{1}{\sqrt{t+x}\sqrt{t+y}\sqrt{t+z}}, dt$$
$$R_F(x,y,z) = \frac{1}{2} \int_0^{\infty} \frac{1}{\sqrt{t+x}\sqrt{t+y}\sqrt{t+z}}, dt $$
See https://arxiv.org/pdf/math/9409227Numerical Computation of Real or Complex Elliptic Integrals for more information.
We also have the special values
$$\eqalign{ R_F(0,1,2) &= \frac{\Gamma({\frac{1}{4}})^2}{4\sqrt{2\pi}} \cr R_F(i,-i,0) &= \frac{\Gamma({\frac{1}{4}})^2}{4\sqrt{\pi}} }$$
$$\eqalign{ R_F(0,1,2) &= \frac{\Gamma({\frac{1}{4}})^2}{4\sqrt{2\pi}} \cr R_F(i,-i,0) &= \frac{\Gamma({\frac{1}{4}})^2}{4\sqrt{\pi}} } $$
It is also related to the complete elliptic integral of the second
kind, $E$,
(elliptic_ec) as follows
$$E(m) = R_F(0, 1 - m, 1) - \frac{m}{3} R_D(0, 1 - m, 1)$$
$$E(m) = R_F(0, 1 - m, 1) - \frac{m}{3} R_D(0, 1 - m, 1) $$
See also: elliptic_ec.
carlson_rj (x, y, z, p) — Function
Carlson’s RJ integral is defined by
$$R_J(x,y,z) = \frac{1}{2} \int_0^{\infty} \frac{1}{\sqrt{t+x}\sqrt{t+y}\sqrt{t+z},(t+p)}, dt$$
$$R_J(x,y,z) = \frac{1}{2} \int_0^{\infty} \frac{1}{\sqrt{t+x}\sqrt{t+y}\sqrt{t+z},(t+p)}, dt $$
See https://arxiv.org/pdf/math/9409227Numerical Computation of Real or Complex Elliptic Integrals for more information.
It is related to the elliptic integral of the third kind (elliptic_pi)
by
$$\int_0^\phi {1\over \left(1+n\sin^2\theta\right) \sqrt{1-m\sin^2\theta}} , d\theta = R_F(c-1,c-m,c) - {n\over 3}R_j(c-1,c-m,c,c+n)$$
$$\int_0^\phi {1\over \left(1+n\sin^2\theta\right) \sqrt{1-m\sin^2\theta}} , d\theta = R_F(c-1,c-m,c) - {n\over 3}R_j(c-1,c-m,c,c+n)$$
where
$c = \csc\phi.$
Note that this differs in our definition of elliptic_pi by the
sign of the parameter $n$.
See also: elliptic_pi.
elliptic_e (phi, m) — Function
The incomplete elliptic integral of the second kind, defined as
$$\int_0^\phi {\sqrt{1 - m\sin^2\theta}}, d\theta$$
$$\int_0^\phi {\sqrt{1 - m\sin^2\theta}}, d\theta $$
See also elliptic_005ff and elliptic_005fec.
See also: elliptic_f, elliptic_ec.
elliptic_ec (m) — Function
The complete elliptic integral of the second kind, defined as
$$\int_0^{\frac{\pi}{2}} \sqrt{1 - m\sin^2\theta}, d\theta$$
$$\int_0^{\frac{\pi}{2}} \sqrt{1 - m\sin^2\theta}, d\theta $$
For certain values of $m$, the value of the integral is known in
terms of gamma functions. Use makegamma to evaluate them.
See also: gamma, makegamma.
elliptic_eu (u, m) — Function
The incomplete elliptic integral of the second kind, defined as
$$E(u, m) = \int_0^u {\rm dn}(v, m), dv = \int_0^\tau \sqrt{\frac{1-m t^2}{1-t^2}}, dt$$
$$E(u, m) = \int_0^u {\rm dn}(v, m), dv = \int_0^\tau \sqrt{\frac{1-m t^2}{1-t^2}}, dt $$
where $\tau = {\rm sn}(u,m) .$
This is related to elliptic_e by
$$E(u,m) = E(\sin^{-1} {\rm sn}(u, m), m)$$
$$E(u,m) = E(\sin^{-1} {\rm sn}(u, m), m) $$
See also elliptic_005fe.
See also: elliptic_e.
elliptic_f (phi, m) — Function
The incomplete elliptic integral of the first kind, defined as
$$\int_0^{\phi} {\frac{d\theta}{\sqrt{1-m\sin^2\theta}}}$$
$$\int_0^{\phi} {\frac{d\theta}{\sqrt{1-m\sin^2\theta}}} $$
See also elliptic_005fe and elliptic_005fkc.
See also: elliptic_e, elliptic_kc.
elliptic_kc (m) — Function
The complete elliptic integral of the first kind, defined as
$$\int_0^{\frac{\pi}{2}} {{d\theta}\over{\sqrt{1 - m\sin^2\theta}}}$$
$$\int_0^{\frac{\pi}{2}} {{d\theta}\over{\sqrt{1 - m\sin^2\theta}}} $$
For certain values of $m$, the value of the integral is known in
terms of gamma functions. Use makegamma to evaluate them.
See also: gamma, makegamma.
elliptic_pi (n, phi, m) — Function
The incomplete elliptic integral of the third kind, defined as
$$\int_0^\phi {{d\theta}\over{(1-n\sin^2 \theta)\sqrt{1 - m\sin^2\theta}}}$$
$$\int_0^\phi {{d\theta}\over{(1-n\sin^2 \theta)\sqrt{1 - m\sin^2\theta}}} $$